archived_user
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- Jun 18, 2026
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How would you solve this algebraically? Can you show your work? Thanks!
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But you didn’t get -120.853%.breadmaker wrote: I get 8.53266% using the CF worksheet.
I don’t see quadratics in the CBoK, Coach!!!S2000magician wrote:
But you didn’t get -120.853%.breadmaker wrote: I get 8.53266% using the CF worksheet.
Nor do I.breadmaker wrote:
I don’t see quadratics in the CBoK, Coach!!!S2000magician wrote:
But you didn’t get -120.853%.breadmaker wrote: I get 8.53266% using the CF worksheet.
still a better love story than Twilight.S2000magician wrote:
Nor do I.breadmaker wrote:
I don’t see quadratics in the CBoK, Coach!!!S2000magician wrote:
But you didn’t get -120.853%.breadmaker wrote: I get 8.53266% using the CF worksheet.
I was answering a question specifically asked about algebra.
Sure you can: we have superscripts in the ribbon, above.Scanspeak wrote: Step 1: Multiply by (1+r)2 (thats squared, I cannot write it properly on here, sorry)
Newton-Raphson or hacksaw!!!!Scanspeak wrote:
Step 1: Multiply by (1+r)2 (thats squared, I cannot write it properly on here, sorry) as proposed by S2000magician
Step 2: You now have 10r2 + 120r + 110 = 120.31 which can be written as 10(r2 + 12r + 11) = 10(12.03)
Step 3: Divide by 10 to get r2 + 12r + 11 = 12.03 We have a quadratic equation here. To solve algebraically, you need ot turn it to a true quadratic equation. We do it by adding 25 to both sides of the equation so equilibrium holds - r2 + 12r + 36 = 37.03
Step 4: Transform left side to (r+6)2 and apply a SQRT to both sides
r + 6 = 6.085
r = 0.085 or 8.5%
This is close to a IRR calculation which is done by trial and error, its just that Excel or the TI calculator are fast at it (and the TI calculator is annoyingly slow when you want to be fast with it). If you cannot convert to an equation that can be solved, you have to put some value for r and see where the equation goes. Then another and after some trial and error you`d get to the actual result, or very close to it.