S2000magician
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- Jun 18, 2026
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Having two degrees in mathematics and having taught university math (calculus, linear algebra, differential equations, topology, combinatorics, abstract algebra, and so on) for twenty years, I’m pretty sure I already knew that. (Yup. I checked: I did already know that.)Aether wrote:The derivative of a constant is actually zero. So this statement doesn’t really make any sense.
Now … here’s the killer: stock prices aren’t constant.
When a stock’s price (S) increases by $1, then … wait for it … the stock’s price increases by … you guessed it! … $1. So the derivative of the stock’s price with respect to the stock’s price – dS/dS – is 1.
I’m not trying to be a smart-aleck here … well, only a little; that relationship is actually important enough to recognize explicitly. When you’re hedging a portfolio it’s good to know how the price of everything in your portfolio will change when one variable (or, perhaps, more than one variable: partial derivatives, anyone?) changes. clever and I were just pointing out one of the everythings.
(I’m not challenging anyone’s intelligence either, Aether: you’re obviously quite sharp. Just having a little fun.)