In the example of Applying Bayes’ Formula in Schweser. (Determining the probability that the boy reaches into the blue bag).
P(A/B)=P(B/A)/P(B)*P(A)
Now the probability of A (probability of selecting the blue bag) is 50%.
Schweser mentions that the reason that the probability of choosing the green or the blue bag is 50% since there are 20 coins in total and ten in each.
What if this wasnt the case? What if there were 5 coins in the blue bag and 15 in the green? How can the probability of picking one of two bags change? Wouldnt it be the same? 50%??
My question is the following? Is it dependent on how many coins there is in each bag?
P(A/B)=P(B/A)/P(B)*P(A)
Now the probability of A (probability of selecting the blue bag) is 50%.
Schweser mentions that the reason that the probability of choosing the green or the blue bag is 50% since there are 20 coins in total and ten in each.
What if this wasnt the case? What if there were 5 coins in the blue bag and 15 in the green? How can the probability of picking one of two bags change? Wouldnt it be the same? 50%??
My question is the following? Is it dependent on how many coins there is in each bag?