archived_user
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- Jun 18, 2026
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Does anyone have an easy way to remember that it’s the trailing P/E that has (1+g) in the numerator as opposed to the leading P/E? I keep forgetting it.
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studyguy18 wrote:
This is how I’ve internalised it, maybe it might help.
Leading P/E is leading the race, therefore it doesn’t need 1 + g to help it catch up… Leading P/E = (1 - b) / (r - g)
Trailing P/E is trailing in the race, therefore help it out with a little (1 + g) yo! Trailing P/E = (1 - b) (1 + g) / (r - g)
…
Stupid I know, but I haven’t messed this up since I started using it haha.