haphols_cfa
New member
- Jun 18, 2026
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Hello - I am getting mixed up with regards to how shortening the measurement interval impacts annualized standard deviation. I can’t seem to understand why the info below would be incorrect.
Shortening the measurement interval for an annualized standard deviation decreases the annualized standard deviation. Here are my calculations:
If StDev is 12% annually
Semi-Annually
Are we able to say the semi-annual StDev is 6%
Annualized StrDev would be 6% * SqRt(2) = 8.48%
Monthly
Are we able to say the monthly StDev is 1%
Annualized StrDev would be 1% * SqRt(12) = 3.46%
Daily
Ex: let’s say daily standard deviation is (12%/250) = .048 StDev per day
Annualized StrDev would be 0.048 * sqRt(250) = .7589%
Conclusion: So, the shorter the measurement interval, the lower the annualized Standard Deviation. Which, when incorporated into a Sharpe Ratio would increase the Sharpe because it appears there is a decrease to volatility.
Where has my logic and/or calculations gone awry? Thank you.
Shortening the measurement interval for an annualized standard deviation decreases the annualized standard deviation. Here are my calculations:
If StDev is 12% annually
Semi-Annually
Are we able to say the semi-annual StDev is 6%
Annualized StrDev would be 6% * SqRt(2) = 8.48%
Monthly
Are we able to say the monthly StDev is 1%
Annualized StrDev would be 1% * SqRt(12) = 3.46%
Daily
Ex: let’s say daily standard deviation is (12%/250) = .048 StDev per day
Annualized StrDev would be 0.048 * sqRt(250) = .7589%
Conclusion: So, the shorter the measurement interval, the lower the annualized Standard Deviation. Which, when incorporated into a Sharpe Ratio would increase the Sharpe because it appears there is a decrease to volatility.
Where has my logic and/or calculations gone awry? Thank you.