Quick question:
Does the persistance factor (1+r-ω) basically replace the (r-g) in the standard Terminal Value formula? Then we discount the Terminal Value back to find the Present Value today. Will “g” always be 0 in the persistance factor? Maybe that is my question.
Does the persistance factor (1+r-ω) basically replace the (r-g) in the standard Terminal Value formula? Then we discount the Terminal Value back to find the Present Value today. Will “g” always be 0 in the persistance factor? Maybe that is my question.