haiderraza wrote:
Tickersu - strong concepts I must say.
Just to clarify my confusion once again, by testing the significance of the slope co-efficient, we intend to say that to does the independent variable significantly (by significantly I mean in a statistical sense) explain the variation in dependent variable or not. and in order to test the significance, we employ two methods i.e confidence interval and t-stat. For the CI, if the interval does not include zero in it, then we can say with x% (Whatsoever the CI is) that slope co-efficient is significantly different from zero which in turn means that it is a statistically significant predictor of the dependent variable [slope is non-zero]. Note, this doesn’t necessarily mean it’s “good” at predicting the DV, just that there is a statistical relationship, and it is better than nothing.
In the case of t-test, is the calculted t stat exceeds the critical t-value in magnitude, then we can say that independent variable is a statistically significant predictor of the dependent variable (the slope is non-zero). Am I correct? Yes
I only made some edits to clarify that statistically significant does not mean it is practically/economically useful. For example, let’s say we have a simple model (x predicts y). The slope could be statistically different from zero (statistically significant), but the R-squared might be very low or the model standard deviation (SER) could be very large (poor explanatory power and accuracy of x for y). This is possible.